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>You are presented with 3 doors. Behind one door is money and behind the other 2 are goats. You pick one door, and another door is open to reveal a goat. You can choose to switch’s doors. If you do, what are the chances yours has the money in it?
It’s 1/2. Your chance of drawing money from the remaining 2 doors is 1/2, not 2/3. Statisticians, in their eternal cope, can never admit it, but they’re dead wrong, this isn’t conditional probability.
It’s 1/2. Your chance of drawing money from the remaining 2 doors is 1/2, not 2/3. Statisticians, in their eternal cope, can never admit it, but they’re dead wrong, this isn’t conditional probability.
