The moon cannot be landed upon. It is its own light source,as proven by basic physics:
Explain how we can take photos while beeing ON the Moon, when its light intensity on earth is 0.1 Lux ?
Without braking laws of physics?
The "inverser square law of light":
L = luminosity/qm
d1 = distance 1
d2 = distance 2
You have a light bulb 1m far away you mesure 1 lx.
If you double the distance you will measure not 1/2 lx . It will be 1/4 lx.
The Intensity korrelates quadratically to the ratio of the meassured distance:
d1 = 1m
d2 = 2m
L1 = 1lux
L1 * (d1/d2)^2 = L2
1lx * (1/2)^2 = 1lx * 1/4 = 1/4 lx
if you measure 1lx at 4 meter distance it will be 4lux at 2 Meter distance:
d1 = 4m
d2 = 2m
L1 = 1lux
L1 * (d1/d2)^2 = L2
1lx * (4/2)^2 = 1lx * 5 = 4 lx
Quadratic relationship. You understand?
Moons distance is 384,400km from earth.
Lets assume the camera (in picrel) is 1m above the ground.
Light intensity of the Moon of 0.1 Lux FROM earth (which is 384,400,000 times the distance of the camera on the moon), that it has to have a light intensity of at least
14,745,600 Lux at 100 km distance from the moon surface.
To comparison:
Suns Light intesnity when you look directly into the sun from earth : 120,000 Lux.
Explain to me, how they made this photo on the moon, or how this dusty dirtball can illuminate the earth with 0.1 lux from that distance.
Flashbangs have a illumination power of 12 million Lux.
We can photograph moon from earth. that works.
because it only has 0.1 lux Intensity.
But there is a thing called physics and the inverse-square-law of light.
It you double the distance the intesity gets quarted.
And if you have 384,400,000 times the distance the intensity gets devided by
384,400,000^2
Does this dusty dirty ball
> picrellooks like it would reflects light at its surface that is 122.880 brighter than sun on earth?
Does anyone here understand physics ?
Here a online calculator for that:
https://calculator.academy/inverse-square-law-calculator/#f1p1|f2p0 
