>>15430383I am circumcised, but such is the way in America...
Anyways, alright assuming you didn't die from that, then you can just plot the gravitational forces over the length of the tunnel through the Earth and make it a function of the position in the tunnel, make it easy by assuming the tunnel is infanatesmally thin so you don't have to worry about the lack mass of the tunnel, assume the Earth is a perfect homogeneously distributed mass of a sphere, solve it by simplified Newtonian graviation. It wouldn't be perfectly precise, but it would be darn near close to the real forces. Even with the simplifying assumptions I'm too lazy to plot that right now, so I'll give you the lazy hand wavey answer.
As you go into the tunnel, near the surface you'll experience 1G of gravitational acceleration towards the center of the earth, as you go down the shaft, more and more of the Earth's mass will no longer be under you, it'll be behind you in the tunnel, the graviational attraction will split up, with you being notably attracted to the mass around you in every direction, with all vectors if attraction totalling a magnitude of 1G of acceleration. In the direction of travel (down the shaft) you'd have less and less gravity acting on you, because you'd be heading towards a force equillibrium. As more and more of the Earth's mass is behind you and you reach the precise center of mass, you'ld be in free fall because you're equally attracted to the mass on all sides of yourself. Gravity would still be acting in you at a total of 1G, but you wouldn't know it, because you'd be in perfect equillibrium at that center point, the apparent gravitational acceleration would be a net of 0G because the acceleration is canceled out.
As you ascend to the other side, you'll leave equillibrium and feel weight again, as the mass of the planet is now more behind you, as you approach the surface, the opposite effect as before will happen, you'l reach 1G downwards as you reach the surface again
