>>4028360>>4028361In a vacuum, thermally conductive bodies will more or less emit as much as they absorb as long as they're not generating heat internally. This means that you reach an equilibrium temperature at the point where power in = power out
Power in is going to be solar irradiance at the car's orbital radius times half the surface area of the car.
Pin = (4 pi R^2 Lo) * (Acar/2)
Power out is going to be power for a radiating black body (more or less) which is going to look like a constant times the car's total surface area, times the temperature to the fourth power
Pout = C Acar T^4
If you put in the appropriate numbers and constants, you get that the equilibrium temperature for the roadster is going to be around 58 C / 136 F. If you add in reflectivity, albedo, etc it ends up closer to about 40 C / 104 F
So no, it's not gonna melt.
