The following problem uses Knuth's up-arrow notation. Explanation below, problem at the bottom.
>Explanation:
>Single arrows:
3↑3 is a way of saying 3^3. Think of it like x↑y, with base x and power y.
>Double arrows:
3↑↑3 is a way of saying 3↑(3↑3), or 3^(3^3), or 3^27. Visually, think of it like x↑↑y is going to be a sort of 'tower' of x's with height y. So x↑↑y is a tower of x's that is y layers high. Double arrows create a kind of 'string' of single arrows as the powers are raised in each layer of the tower.
>Triple arrows:
In the same way that double arrows create a string of single arrows, a triple arrow creates a string of double arrows. So 3↑↑↑3 is creating a string of 3↑↑3's all the way along. So 3↑↑↑3 is 3↑↑(3↑↑3). Since 3↑↑3 is about 7.6 trillion, what you're doing with 3↑↑(3↑↑3) is making a tower of 3's (your base on the left) about 7.6 trillion layers high. Imagine 3 to the power of 3 to the power of 3... and so on about 7.6 trillion times. That is 3↑↑↑3.
>Quadruple arrows:
Follow the pattern. What will 3↑↑↑↑3 be? If you figured out it would be 3↑↑↑(3↑↑↑3), you're beginning to get the hang of this. This will be a faster way of saying 3↑↑(3↑↑(3↑↑... (3↑↑3)). The total amount of 3↑↑3's in those ellipses? 3↑↑↑3. Remember? Our 7.6-trillion-and-change high power tower of 3's? Yeah, that many.
>Problem:
Refer back to 3↑↑↑↑3. That number is M1 (meme level one) for our purposes. Now take another pair of 3's. Insert M1 arrows between that pair. That number is M2 (meme level two, incredibly dank). Now take another pair of 3's and insert M2 arrows between that pair. Repeat this process, adding another level to your increasingly large number. Repeat until you reach M64. That is your meme number. The last three digits of M64 plus two are your suggestion, going by National Dex number.
*OR BANDED SEEDOT.*