/vp/ - Pokémon » Thread #42374772

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Anonymous Sun 12 Jan 2020 23:29:19 No.42374772 View View Reply Original Report

Quoted By: >>42374804 >>42374855 >>42374933 >>42375078 >>42376010 >>42377258 >>42377272 >>42378003

Alright anons, riddle me this since you're so good at math.
Given that there's 890 unique species of Pokemon, and you have 6 party slots in your team:
a) How many unique combinations of Pokemon can you have?
b) How many (not unique) combinations of Pokemon can you have?
Result must contain a factorial.

Anonymous

Anonymous Sun 12 Jan 2020 23:31:30 No.42374804 Report

Quoted By:

>>42374772
https://www.youtube.com/watch?v=OZzIvl1tbPo

Anonymous

Anonymous Sun 12 Jan 2020 23:34:32 No.42374855 Report

Quoted By: >>42374890 >>42375263

>>42374772
>factorial
wrong, that's if you can't have dupes
>how many unique combinations of pokemon can you have
it's either 890^6 or 6^890 but i can't remember which

Anonymous

Anonymous Sun 12 Jan 2020 23:36:39 No.42374890 Report

Quoted By: >>42375263

>>42374855
>6^890
Should be this one

Anonymous

Anonymous Sun 12 Jan 2020 23:39:29 No.42374933 Report

Quoted By: >>42377626

>>42374772
Practically you wouldnt be using NFEs apart from a few eviolite cases

Anonymous

Anonymous Sun 12 Jan 2020 23:48:38 No.42375078 Report

Quoted By:

>>42374772
I won't make your homework, OP.

Anonymous

Anonymous Mon 13 Jan 2020 00:02:52 No.42375263 Report

Quoted By:

>>42374855
>>42374890
Simplify it to 1 slot to check your work. This is easy, because there are 890 ways to have a team of 1 if there are 890 different Pokemon to choose from.
1^890=1
890^1=890
With a 2nd slot, you have 890 possible ways to add a Bulbasaur to the team, 890 possible ways for Ivysaur, 890 ways for Venusaur etc. for each of the 890 Pokemon, so 890x890, not 2x890, and certainly not 2^890.
For a team of 6, it's 890x890x890x890x890x890, or 890^6. This does include teams of the same 6 Pokemon, only in a different order, though.

Anonymous

View Same Google ImgOps iqdb SauceNAO pokeymath.png, 7KiB, 375x266

Anonymous Mon 13 Jan 2020 00:57:33 No.42376010 Report

Quoted By:

>>42374772
a) is ~683 Trillion while b) is ~497 Quadrillion

Anonymous

Anonymous Mon 13 Jan 2020 02:17:34 No.42377258 Report

Quoted By:

>>42374772
if we're going for no duplicate mons on teams, then the result is equal to 890*889*888*887*886*885, as each pokemon we add subtracts 1 from the total in order to keep it unique. this totals in at 4.88e17 combos, or 48.8 quadrillion.
I would do the total with unique lines too (can't have charmander and charizard on same team, for example) but it's 2am and I don't want to get into if split evos count at this time.

Anonymous

View Same Google ImgOps iqdb SauceNAO 1577983607707.jpg, 1MiB, 1920x1920

Anonymous Mon 13 Jan 2020 02:18:45 No.42377272 Report

Quoted By: >>42377293 >>42377830 >>42377888

>>42374772
Who said I was good at math?
I'm not. I failed Calculus 1 three times.

Anonymous

Anonymous Mon 13 Jan 2020 02:20:06 No.42377293 Report

Quoted By:

>>42377272
Don't give up, anon.

Anonymous

View Same Google ImgOps iqdb SauceNAO 4 moves 5000 IQ.jpg, 200KiB, 640x552

Anonymous Mon 13 Jan 2020 02:26:28 No.42377399 Report

Quoted By:

>says unique combinations
>dur hur 890 - 6
You forget those pokemon also have unique natures which affect stats, as well as IV pools that also once again affect stats, oh and you know fucking abilities/HA, and to top it off, egg moves
Get fucked.

Anonymous

Anonymous Mon 13 Jan 2020 02:43:01 No.42377626 Report

Quoted By:

>>42374933
Not all of us just magically start with fully evolved starters, nigwig.

Anonymous

Anonymous Mon 13 Jan 2020 02:57:08 No.42377830 Report

Quoted By:

>>42377272
>I failed Calculus 1 three times.
Teacher kept deducting points cause I was doing my math by hand instead of by calculator.

Anonymous

Anonymous Mon 13 Jan 2020 03:00:35 No.42377888 Report

Quoted By:

>>42377272
How??

Anonymous

Anonymous Mon 13 Jan 2020 03:08:50 No.42378003 Report

Quoted By:

>>42374772
I would kill for this in high res for a phone wallpaper

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