>>1007804>1. We mix 400 ml HNO3 solution with a pH of 2 with 400 ml HNO3 solution with a pH of 1. What is the pH of the final solution?pH = -log[H+]
pH = 2 -> 10^-2 M = [H+] = 0.01 M
0.01 M x 0.400 L = 0.004 mol of H+
pH = 1 -> 10^-1 M = [H+] = 0.1 M
0.1 M x 0.400 L = 0.04 mol of H+
total volume after mixing is 0.800 L
molarity after mixing is total mol H+ / total volume
(0.004 + 0.04) mol / 0.800 L
0.044 mol / 0.800 L = 0.055 M H+
pH = -log[H+]
pH = -log[0.055]
pH = 1.260
it makes sense that it's between 1 and 2
