>A ladder of mass m = 8kg and length l = 10m is leaning against a wall at the heigth of h = 8m from the ground. Find the ground and wall reaction forces.

Now, it is obvious that Fgy = mg = 78.48N. I know two ways to solve the rest but I get different results:

>the torque method
We'll take the point where the ladder touches the ground as the point of rotation.
Tw = Tm (torque caused by the wall is equal to the torque caused by the mass (weight))
Tw = Fw x h = Fw x 8m
Tm = 3m x mg = 3m x 78.48N = 235.44Nm (3 because we have a 3-4-5 triangle but scaled by 2, so the center of the weight of the ladder pulls toward the half of the leg of length 6)
Solving all of this we get that Tw = Fgx = 235.44Nm / 8m = 29.43N.

>the sine theorem method
We know that sin a = h/l = 0.8, so a = 53.13°. b = 90° - a = 36.87°. Now, we can construct a similar triangle with angles a and b but with legs of Fgx (opposite of b) and Fgy (opposite of a). Hypotenuse would be Fg then. Using sine theorem, we have that:
Fgx / sin b = Fgy / sin a = Fg.
Now, simply solving for Fgx, we get that Fgx = Fgy (sin b / sin a) = 78.48N x 0.75 = 58.86N.

So you see that using these two methods we get two different answers that are different by exactly the factor of 2. Where am I going wrong here and which is the correct answer?