>>351240I think there's a mathematical way to figure out a-f, but it's very complicated and probably out of the class's scope. I found that making the easiest initial guess led to
a = d = 4 (my guess)
b = e = 1
4f + 1 + 4c = -27 ---> 4(f + c) = -28
f + (6/f) = -7 since c = 6/f. At this point you can guess, but just to be analytical:
f(f + (6/f) + 7) = 0
f^2 + 7f + 6 = 0
Quadratic formula on this says that
f = (-7 plus or minus sqrt(25))/2 = -6 or -1
If we make f = -6, then c = -1 and vice-versa.
I made that post, then felt bad because I didn't try solving the equation myself to verify that it's doable analytically. I was still wrong by telling you to guess for 4 different variables, when only 2 is necessary.
