/wsr/ - Worksafe Requests » Thread #801387

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306KiB, 1080x2340, Screenshot_20200409_000340_com.whatsapp.jpg

Anonymous Wed 08 Apr 2020 21:12:02 No.801387 View View Reply Original Report

Quoted By: >>801394

Solve image related question. The correct answer is (819)(Pi). From the answer I got that the radius is equal to 50. However I want the steps to get (819)(Pi). Thanks in advance

Anonymous

Anonymous Wed 08 Apr 2020 21:20:54 No.801394 Report

Quoted By: >>801404

>>801387
Let R be the big radius, r be the small radius:
>horizontal
2R = 2r + 18
Therefore
R-r = 9
Which is the length of the segment between the two midpoints.

Now use Pythagoras to find
>vertical
2R = 2*10 + 2*√(r^2 - 9^2)

Now just solve for R and r.
The green area is just
pi * R^2 - pi * r^2

Anonymous

Anonymous Wed 08 Apr 2020 21:24:10 No.801398 Report

Quoted By:

The area of the big disk is
π·50^2
The area of the small disk is then
π·41^2
The difference is π·(50^2 - 41^2) = 819π.

Anonymous

Anonymous Wed 08 Apr 2020 21:41:31 No.801404 Report

Quoted By:

>>801394
Thank you very much. I already got the horizontal equation but I got stuck with the vertical one. Sorry for responding late, it took me a bit too while to understand the vertical equation.

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