>>983120I might be wrong, but you can't. I made pic related. If you take the middle points of a square, then you end with another square in the center which is half of the area of the original square, not only that but you end with four triangles of equal area, I named said triangles B and the remaining parts a, b, c, d. So my equations are
B + a = 20
B + b =32
B + c = 16
B + d = A
Then I used the property of the center square
a+b+c+d = 4B
Then unless I'm forgetting about another property regarding squares you can't go further, since you have five equations and six variables which results in a system with infinite solutions. I gave values to B and ended with different solutions, there was a program to graph different geometrical forms sadly I can't recall its name so I can't graph said forms to verify they are indeed squares
