/wsr/ - Worksafe Requests » Thread #126190

[19 / 3 / ?]

13KiB, 600x366, CjDGUT7VEAY1hUO.jpg orig.jpg

Anonymous Sun 22 May 2016 10:30:40 No.126190 View View Reply Original Report

Quoted By: >>126195

Requesting to solve this equation.

There's an image made by a fan artist and they locked it away, and the password is the answer to this equation.

Thanks.

Anonymous

Anonymous Sun 22 May 2016 10:47:10 No.126195 Report

Quoted By: >>126197

>>126190
type that shit into wolfram alpha
here's a simpler example
http://www.wolframalpha.com/input/?i=lim+x+to+infinity+1%2Fx

Anonymous

Anonymous Sun 22 May 2016 10:50:35 No.126197 Report

Quoted By: >>126200 >>126201

>>126195
Math and calculations aren't my thing. If the answer is 0, then it's probably incorrect because I still can't access the file.

Anonymous

Anonymous Sun 22 May 2016 10:54:47 No.126200 Report

Quoted By: >>126206

>>126197
I wasn't suggesting that the answer to the shit you posted was zero.
Rather the limit of 1/x as x goes to infinity (a simpler example of a limit) is zero.
I wanted you to use the syntax of the example to get wolfram to do the work for you.

see this is closer to the expression you posted
https://www.wolframalpha.com/input/?i=lim+h+to+infinity+%281%2B+%28243%2Fh%29%29^h

Anonymous

Anonymous Sun 22 May 2016 10:55:54 No.126201 Report

Quoted By: >>126206

>>126197
>here's a simpler example

Means he didn't put in the exactly what you asked for read before you write.

http://www.wolframalpha.com/input/?i=lim+x+to+infinity+%281%2B243%2Fx%2B2520%2F%28x^2%29%2B3216%2F%28x^3%29%29^%28x%2F3%29

highschoolstudent

highschoolstudent Sun 22 May 2016 10:58:01 No.126203 Report

Quoted By: >>126206

I'd say it's equal to 1 but I'm not really sure about this

Anonymous

Anonymous Sun 22 May 2016 10:58:21 No.126204 Report

Quoted By: >>126206

e^81 ?

Anonymous

Anonymous Sun 22 May 2016 11:03:46 No.126206 Report

Quoted By: >>126207 >>126378

>>126200
>>126201
>>126203
>>126204
I entered 1, nothing. I entered e^81, nothing. I entered 1.5060973e+35, nothing. Image is still unlocked.

Anonymous

Anonymous Sun 22 May 2016 11:06:47 No.126207 Report

Quoted By: >>126211

>>126206
what is that below the expression?
hiragana?
maybe you need to incorporate that as well

Anonymous

Anonymous Sun 22 May 2016 11:15:02 No.126211 Report

Quoted By: >>126216

>>126207
の上ワケタがパスワード

I think it means the above equation is the password. Not sure about ワケタ (Waketa). It means to divide into, to split into, to separate, to sort out, to classify.

Anonymous

View Same Google ImgOps iqdb SauceNAO wrongmaybe.png, 32KiB, 676x446

Anonymous Sun 22 May 2016 11:17:37 No.126213 Report

Quoted By: >>126214 >>126215

This is probably wrong, but this is all I got from chucking it into wolfram.

Anonymous

Anonymous Sun 22 May 2016 11:18:30 No.126214 Report

Quoted By:

>>126213
you used both x and h, that doesn't jibe with op's pic

Anonymous

Anonymous Sun 22 May 2016 11:19:14 No.126215 Report

Quoted By:

>>126213
oh shit, i mixed up x and h. It comes out as e^81 instead of 1.

Anonymous

Anonymous Sun 22 May 2016 11:30:24 No.126216 Report

Quoted By: >>126218

>>126211
7ケタ not ワケタ

Anonymous

Anonymous Sun 22 May 2016 11:35:51 No.126218 Report

Quoted By: >>126381

>>126216
Author says "input seven upper digits,please."

Anonymous

Anonymous Sun 22 May 2016 11:58:34 No.126222 Report

Quoted By:

OP here. The answer is 1.5060973e+35 but the author stated the answer is 7 digits only, so "1506097".

Thanks for the help, everyone.

Anonymous

Anonymous Sun 22 May 2016 12:02:12 No.126223 Report

Quoted By:

First it's easy to find a lower bound:
lim (1 + (243/h) + (2520)/h^2 + (3216/h^3))^(h/3)
>= lim (1 + (243/h))^(h/3)
= e^81

Now for every epsilon>0 there is a h_0 such that for all h > h_0
(2520/h) + (3216/h^2) < 3*epsilon
Therefore
lim (1 + (243/h) + (2520)/h^2 + (3216/h^3))^(h/3)
<= lim (1 + (243/h) + (3*epsilon/h))^(h/3)
= e^(81 + epsilon)
Since this is true for every epsilon>0 we must have
lim (1 + (243/h) + (2520)/h^2 + (3216/h^3))^(h/3) <= e^81

Together with the lower bound this gives
lim (1 + (243/h) + (2520)/h^2 + (3216/h^3))^(h/3) = e^81

Anonymous

Anonymous Sun 22 May 2016 18:21:21 No.126378 Report

Quoted By:

>>126206
Have you considered that the image is just a way for them to remember their password and that the password is not actually the solution to the problem?

My password recovery questions are rarely answered using legitimate information about me, especially easily obtainable information.

Anonymous

View Same Google ImgOps iqdb SauceNAO 1442284582894.jpg, 94KiB, 775x719

Anonymous Sun 22 May 2016 18:22:51 No.126381 Report

Quoted By:

>>126218
enter 2432520

those are the 7 upper digits

Capcode	All Only User Posts Only Verified Posts Only Moderator Posts Only Manager Posts Only Admin Posts Only Developer Posts Only Founder Posts
Show Posts	All Only With Images Only Without Images Only Spoiler Images Only Non-Spoiler Images
Deleted Posts	All Only Deleted Posts Only Non-Deleted Posts
Ghost Posts	All Only Ghost Posts Only Non-Ghost Posts
Post Type	All Only Sticky Threads Only Opening Posts Only Reply Posts
Results	All Grouped By Threads
Order	Latest Posts First Oldest Posts First

On these archives

Your latest searches